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So I've tried the math and not sure if I'm getting it right.
Motor is at 128 transfers currently with 72mm stroke. Has 130.3 rod. If I put a 4mil crank(76mm) in it where are my transfers going to end up? I think in the 134 area, but can't seem to figure out the math. Can someone with a program help me out? What I need to know is where they will end up at and how much I will need to take off the bottom of the cylinder (smaller spacer) to get them in a respectable area again.(Around 130)
Maybe some one can point me in the right direction of some free software that can help me with this? I've tried a few on line calculators with no luck.
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250r 4mil stroke in already ported cylinder How much do I need to drop the cylinder?
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- Idle
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Posted 13 September 2010 - 06:43 PM
#2
- 3/4 THROTTLE
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Posted 14 September 2010 - 05:24 AM
I'll make this easy for you for the transfer timing. Assuming you run no spacer plate (which is what you will have to do), you are going to be at 134* if the trans are at 128* right now. Every .010 you drop the cylinder will take off exactly 1 degree of trans timing. So you would have to move the jug down another .040 to get to even 130*.
slow 421 dragger, duner banshee, 310R duner
Wife's 370R Fastest true gas Pro-X Honda 4.29 in sand 4.17 in dirt 300ft on a dune chassis.
2-cycle generator and an old school Lawnboy to mow the yard!
It aint no joke if it blows blue smoke
Wife's 370R Fastest true gas Pro-X Honda 4.29 in sand 4.17 in dirt 300ft on a dune chassis.
2-cycle generator and an old school Lawnboy to mow the yard!
It aint no joke if it blows blue smoke
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